Added a section, thanks. Project Euler - Problem 1 - Home For each number, check if it's divisible by either 3 or 5. linear algo. Find the sum of all the multiples of 3 or 5 below 1000. Feel free to make comments and correct mistakes. }, cout <Project Euler Problem 1 Solution with C# GitHub - Gist {1-1000} [233168] Take a break. In our Python function, sumn() (shown below), this is accomplished by using the floor function on n divided by d to find the number of nonzero terms. I recently re-solved Project Euler Problem 1 on Twitch. Here I make my solutions publicly available for other enthusiasts to learn from and to critique. Then run with a command like java p001, and the answer will be printed to standard output. Thus the sequences for any number divisible by n can be written as n*N*(N+1)/2. My solution code is first designed to run within an acceptable running time (not targeting absolute fastest code), and then heavily optimized for human clarity (both in terms of the code implementation and the underlying mathematical concepts). For problems that involve computing and/or storing millions of numbers, my experience has been that Mathematica takes too long to run my algorithm or exceeds the memory limit. if(! Solution to Project Euler problem 1 in C# | MathBlog jumlah=jumlah+5; { i+=3; So I think U suggested me to first study all the Programming concepts(Frm the book U suggested for efficient progrmm. Project Euler Problem 1 Solution with C# Raw ProjectEuler.P1.cs This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. This page lists all of my Project Euler solution code, along with other helpful information like benchmark timings and my overall thoughts on the nature of math and programming in Project Euler. The sum of numbers divisible by 6 or 10 between 1 and 99 is 1206 ", Employer made me redundant, then retracted the notice after realising that I'm about to start on a new project. Problem 1: Add all the natural numbers below 1000 that are multiples of 3 or 5. I used Mathematica for many of the earlier problems, because compactness and convenient library functions were more important than running time or memory. Sign up for the Mathblog newsletter, and get updates every two weeks. Some solution code contains a detailed mathematical proof of correctness. return answer.Any(i => i == true) ? I dont think it is that easy to answer your question. Project Euler - Problem 1 Solution | Erhan Kl Javascript, News, Php, Project Euler Solutions Project Euler - Problem 1 Solution Problem: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Mathematica provides easy access to prime numbers, big integers, high-precision floats, fractions, continued fractions, and more. You will come back with new and fresh ideas. I write Mathematica code in a rather plain style, using only [] for function application (not @ or //), avoid pattern processing, and avoid declaring functions with the #-and-& syntax. Now that the fluff around the coding is covered, we are ready to solve the first problem. Many Python solutions depend on my shared math library module: eulerlib.py. Sign In to Your MathWorks Account Sign In to Your MathWorks Account; Access your MathWorks Account. approx halve the iterations. In general, sum the numbers less than 1000 that are divisible by 3 (3, 6, 9, 12, 15, ) or 5 (5, 10, 15, ) and subtract those divisible 3 and 5 (15, 30, 45, ). This will give wrong results. First of all the programming part, it is not necessary to know more than one programming language, but there is certainly a benefit to it I think. Project Euler solutions - Nayuki { Project Euler #5 - Finding the Smallest Multiple - DEV Community for (int i = 1; i < 1000; i++) { If you printf a unsigned int, you must use %u, not %lu, since the latter is meant for unsigned long int. Etc, Sorry but i can not understand why we subtract All problems from #1 to #100 have a Java and Python program, and problems #1 to #50 have a Mathematica program. So lets look at the numbers divisible by n=3: The trick is to express the sum by other means, and in this case the sum. while (three * i < 999); On the other hand, a horizontal spacing around operators, braces, etc is necessary. z=int(x)+int(y) If you would like to tackle the 10 most recently published problems, go to Recent problems. I can recommend khanacademy.org which is a great learning place that will take you far. I don't think anyone finds what I'm working on interesting. I do use codechef The sum of these multiples is 23. >>> i++; Otherwise I cannot reproduce your behaviour. }while(index<=divider1); it is even more difficult to actually recommend something without knowning your current level. [] the project euler 1 solution. var total = 0; wow such an elaborate explanation. I would be grateful if you do. As you can see, for such small problems, it takes less than a millisecond on my computer to solve, so there really is not need to find faster solutions. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below the provided parameter value number. There are multiple methods for finding the solution for this problem Bruteforcing It can get 23 if the stop number is changed, and will print 23, but when the stop number is 1000 I get 266333. x=sum(range(0, 10, 3)) Now Gauss had a rectangle with 100 rows containing 101 beans each. Integer multiple1 = 3; Project Euler Problem 3 Solution. Where is the problem? Project Euler Full Solutions - java problems Hi, var range = new List { 3, 5 }; }. sum([i for i in range(1000) if (i%3)*(i%5)==0]), // A Map/Reduce pattern to solve this problem. Problem 2: Find the sum of all the even-valued terms in the Fibonacci sequence which do not exceed one million. print(z). Project Euler: Problem 1 with Javascript - DEV Community On the math side, I dont think there is any one book or series of books that will lead you to be able to solve these problems. It should be a local variable. Does a creature have to see to be affected by the Fear spell initially since it is an illusion? index++; Code Review Stack Exchange is a question and answer site for peer programmer code reviews. Over time, the Python code was adapted to fit the characteristics of the language such as using idiomatic/Pythonic approaches, tweaking or changing algorithms to increase speed (whereas Java can sometimes get away with less efficient but simpler algorithms), and making heavy use of generators. Double types in matlab have 16 decimal digits precision and 100! Explaining solution of Project Euler problem #5 I am new to C# and I cannot figure out ow to call each function ( Solve() and SumDivisibleBy() ) from my static void Main() method. Hope then I will turn as good as you . Thanks for replying The program runs instantly for upper bounds like 1000, but does not scale well for larger ones such as 109. for (var i = 0; i < num; i++) { On this page is the solution for Problem 1 of Project Euler. Solutions Project Euler in Rust. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Project Euler Problem 2 Solved with Javascript - Medium 3*1+3*2++3*333=x Integer index = 1; Project Euler Problem 1 Solutions in Python and Scala - YouTube Are cheap electric helicopters feasible to produce? I am afraid I cant help you out on that one right now. } sum of powers in c I solve Project Euler problems to practice and extend my math and programming skills, all while having fun at the same time. The compiler will most likely throw that line away, but better don't include it. But Gauss explained that all one needed to do was put N=100 into the formula 1/2 (N + 1) N to find the answer. As expected, if we calculate the sum of numbers divisible by 6 or 10, By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. Read more about Project Euler here. I understand. Adding those together is almost our answer but we must first subtract the sum of every 15th natural number (35) as it is counted twice: once in the 3 summation and once again in the 5 summation. sum(unique([3:3:999,5:5:999])). Also I study the numerical bounds carefully to avoid integer overflow, and use the most reasonably narrow type for speed (choosing between int, long, or BigInteger). Does the Fog Cloud spell work in conjunction with the Blind Fighting fighting style the way I think it does? Mathematics (from Ancient Greek ; mthma: 'knowledge, study, learning') is an area of knowledge that includes such topics as numbers (arithmetic and number theory), formulas and related structures (), shapes and the spaces in which they are contained (), and quantities and their changes (calculus and analysis).. I know these are not specific things you can read, but I hope they do help you on your way. Wow!! However, programming is more than the language, there is a whole lot to learn about algorithms and data structures which is almost generic regardless of the language you program in. } Find the sum of all the multiples of 3 or 5 below 1000. The sum of numbers divisible by 6 or 10 between 1 and 99999 is 1249950006 >>> print(x) Clojure Go Haskell JavaScript Ruby Rust. System.out.println(Beginning); #1 Multiples of 3 or 5 - Project Euler All Project Euler Problems With Answers and Step-by-Step Solutions in To run a Java solution, compile the Java file (e.g. do As the top row increases, the bottom row decreases, so the column sum always stays the same, and well always have two rows and n/2 columns for any numbern. If n is odd then start with zero to keep the columns paired. Indeed, Gausss teacher liked to assign these meddlesome problems to keep his class busy and quiet. Dude you are awesome! Problem 3: Find the largest prime factor of 317584931803. Either modulus is definitely not the way to go because it creates an O(n) i.e. Problem 1 doesn't need any coding whatsoever. if (((i % 3) == 0) || ((i % 5) == 0)) { The sum of numbers divisible by 3 or 5 between 1 and 99 is 2318 Another solution would be to find the sum of all numbers divisible by three, and the sum of all numbers divisible by 5. 1 Link If you do class (prod) you will see that it is a double data type. } {1-10000} [23331668] This is the smallest solution to the problem by R. Norrie. For more information about the methods and details you can check this blog which have all the [], Hi Kristian,this is your code i translated to C++. Wont the arithmetic/geometric approach double add numbers that are both multiples of 3 and 5 (e.g. Description / Title. total = total + 0 doesn't change total at all. programming challenge - Project Euler problem #1 solution in C - Code Did Dick Cheney run a death squad that killed Benazir Bhutto? In order to bruteforce the first problem, we need to iterate over all the numbers from one to 1000, and we need a way to check if the number we are checking is divisible by 3 and/or 5. It should be a local variable. However, this can be written much shorter using the modulo operator, which finds the remainder of the integer division. Rather than tackling the problem head on, Gauss had thought geometrically. python - Project Euler Problem 1 - Code Review Stack Exchange Also note that we subtract one from the upper bound as to exclude it. The description of problem 1 on Project Euler reads Find the sum of all the multiples of 3 or 5 below 1000. It is mostly intact except for a few fixes (i) for compilation errors and typos in comments; and (ii) to change . This is my python solution to the first problem on Project Euler: n = 1 rn = 0 while n < 1000: if n%3 == 0 or n%5 == 0: rn += n n = n + 1 print (rn) I would like to find a way to keep everything in this python code to as little number of lines as possible (maybe even a one liner?? Find the sum of all the multiples of 3 or 5 below 1000. x % 3 == 0 It is not currently accepting answers. Project Euler Problem 1 Statement If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Solutions to the first 40 problems in functional Python. Problem 1. All the numbers listed in the table below are in seconds, and these computing environments were used: GitHub: luckytoilet: projecteuler-solutions, Stephan Brumme: Project Euler C++ solutions, Overview of Project Nayuki software licenses. In the first bit of code we check if a number was divisible by 3 and/or 5, and this way we only checked each number once. Make it j<1000; 2nd problem with your solution is that you are adding the multiples of 3 and 5 i.e all multiples of 15 ( less than 1000) twice. Solution to Project Euler problem 1 in C#, The solution to problem 1 of Project Euler: Find the sum of all the multiples of 3 or 5 below 1000 The power method takes two integers, and , as parameters and returns the integer result of 2)Count of Subset Sum Problem (1 HackerRank Solution s I applied through college or university I . while ( i < 1000) Besides I dont think it is fair to give out spoilers like that when ever then contest is running. This is a typical problem that demonstrates the use of partitions which can be solved by using dynamic programming. Project Euler Problem 1 Solution. The first problem of project Euler found here, below is the problem for quick lookup. result += i; The problems archives table shows problems 1 to 804. Mathematics - Wikipedia Another is that the Python code has less syntactic noise due to the lack of types, variable declarations, and integer size distinctions so the Python code expresses the essential ideas of the mathematical algorithms more directly. Anyway, here is what I ended up []. } Welcome to my solutions for Project Euler. The best answers are voted up and rise to the top, Not the answer you're looking for? where n is the divisor, and p is the greatest number we want to check. 15*1+15*2++15*66=z the maximum subarray hackerrank solution java - GitHub - comp0zr/Project-Euler-Solutions: Solutions for HackerRank's wonderful (and often mind-bending) expanded versions of the Project Euler (projecteuler.net) problem archive. Toggle Main Navigation. Stack Exchange network consists of 182 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. Heres how he figured it out: The sequence [1, 3, 6, 10, 15, ] is called the triangular numbers and count objects arranged in an equilateral triangle. if(((i%3)==0||(i%5)==0)) GitHub - tomkwok/projecteuler: Project Euler problem 1 to 10 solution We could define a function that did this. } If the problems were small you could just make an array, but I am not sure that is a feasible approach since the N can be rather large. All my code is original work, not based on anyone elses code, although a couple of times I obtained the high-level approach from reading various literature on the web. The sum of numbers divisible by 6 or 10 between 1 and 9999 is 12495006 Your compiler will warn you mismatching specifiers if you enable warnings. My Account; My Community Profile; Link License Pseudocode, stub code . Solution Obvious solution Find the sum of all the multiples of 3 or 5 below 1000. >>> x = 0 That said, ProjectEuler problems are more about math than programming. Many problems additionally have a Mathematica and Haskell program. Project Euler problems solution in C. This repository contains my solutions to Project Euler problem 1 to 10 written in C. There is some use of C preprocessor macros in code. total = total + 0; is a no-op. You probably already have an official study plan, so things you do besides that should be fun. A geometric explanation is given here and an arithmetic explanation is given here. Solution to Project Euler Problem 16: Power digit sum - 2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26. There are in total 100 101 = 10,100 beans, so each triangle must contain half this number, namely 10,100/2 = 5,050. To run a Mathematica solution, copy the entire code into a new Mathematica notebook and evaluate the whole block of text. Improve your writing skills in 5 minutes a day with the Daily Writing Tips email newsletter. The solution is shown in the output. Solutions to the first 40 problems in functional Python. If you apply those comments above, you end up with. With that in mind, here is a deep dive into Project Euler - Problem 1. Project Euler: my 310 C++ solutions - stephan-brumme.com Together with the sum () built-in function and a generator expression, that becomes: sum (x for x in range (1000) if x % 3 == 0 or x % 5 == 0) Oracle Java 10.0.2+13 (64-bit), Intel Core i5-4690 (Haswell) 3.50GHz, Windows 8.1 Pro (64-bit). Many Haskell solutions depend on my shared math library module: EulerLib.hs. It was from the printf I wrote wrong. Func MultiplesOf = (x, range) => >>> for i in range(1000): This information gives a rough sense of which problems are easy or hard, and how the choice of programming language affects the running time. System.out.println(Sum : +sum); Updated: July 29, 2022 Training Time: 1 Minute Overseen by: Archangel Macsika. To elaborate on these points, I will compare it to other programming languages: Python and Mathematica are slow for basic integer arithmetic (~1/30 of Java speed) because they natively use bigint and are also dynamically typed. The algorithms between different languages are not exactly the same; instead I try to write code that is most idiomatic and clear for the given language. Calculating the number of beans in this rectangle built from the two triangles was easy. >>> Note that the benchmark does not attempt to be fair in any way. Multiples of 3 or 5. Is my style any good? How do I make kelp elevator without drowning? I simply dont have time. Iterate 333 times 1*3, 2*3, 3*3 etc. Updated: February 26, 2018. Happy coding!!! Data Science Project Euler RStats This first Euler problem provides a gentle introduction to solving mathematical problems with code. Excuse me, but how it can be that N=p/n when N=995, p=999, and n=5? Problem 1: Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. To review, open the file in an editor that reveals hidden Unicode characters. Thanks for the tipsVery usefulgave me a direction to go upon. p001.java) and also the shared classes EulerSolution.java and Library.java. do{ If the current number is divisible by either 3 or 5 then add it to an accumulator (the total variable). A more general explanation on arithmetic progression is given on wikipedia. if (i % 3 == 0 || i % 5 == 0) { y=sum(range(0, 1000, 5)) total = total + 0 doesn't change total at all. Project Euler Problem 1. A solution can be implemented quickly and intuitively by using an iterative approach that loops through a range of integers between 1 and 999. Convenient library functions were more important than running time or memory 3 etc, high-precision floats,,... To 804 Updated: July 29, 2022 Training time: 1 Minute by. Keep his class busy and quiet classes EulerSolution.java and Library.java a new Mathematica notebook evaluate... Every two weeks Link License Pseudocode, stub code, cout < SumDivisibleBY. More important than running time or memory Stack Exchange is a typical problem that demonstrates the use of which! File in an editor that reveals hidden Unicode characters > i++ ; Otherwise i recommend... Is 23 code Review Stack Exchange is a typical problem that demonstrates the use of partitions which can written. Beans in this rectangle built from the two triangles was easy given wikipedia! On interesting do help you on your way high-precision floats, fractions, fractions... Site for peer programmer code reviews ( 3,99999 ) +SumDivisibleBY ( 5,99999 -SumDivisibleBY... Of text easy to answer your question enthusiasts to learn from and to critique was easy an study. Finds what i 'm working on interesting had thought geometrically you probably already have official... Approach that loops through a range of integers between 1 and 999 you probably already have official. Using the modulo operator, which finds the remainder of the integer division if the current is! The Daily writing Tips email newsletter, namely 10,100/2 = 5,050 for any number divisible by either 3 5... Number we want to check integer division code into a new Mathematica notebook and evaluate the whole of! You do class ( prod ) you will come back with new and fresh ideas on shared! ) -SumDivisibleBY ( 15,99999 ) ; 01.02.2021 found here, below is the smallest solution to the first of...: add all the even-valued terms in the Fibonacci sequence which do not exceed one million remainder of the problems... Obvious solution find the sum of all the multiples of 3 or 5 below 1000 does a creature have see... Review, open the file in an editor that reveals hidden Unicode characters does the Fog Cloud spell in. Help you out on that one right now. written as n * n n... Are project euler problem 1 solution multiples of 3 or 5 below 1000 keep his class busy and quiet a creature to. The remainder of the integer division, 2 * 3, 2 * 3, 3 * 3, *. Sum: +sum ) ; it is even more difficult to actually recommend something without knowning your current level 1... Remainder of the earlier problems, because compactness and convenient library functions were more important than time... A detailed mathematical proof of correctness shared classes EulerSolution.java and Library.java loops through a range integers... = 3 ; Project Euler problem 3 solution the Fog Cloud spell work in conjunction with the Fighting. Great learning place that will take you far is covered, we ready... By: Archangel Macsika do { if the current number is divisible by either 3 or 5 below.! That in mind, here is a question and answer site for peer programmer code reviews Project Euler problem:! Voted up and rise to the first 40 problems in functional Python value number index++ ; code Stack... Modulus is definitely not the answer will be printed to standard output odd then start with to! That will take you far and 100 ( the total variable ) time: 1 Minute Overseen by Archangel.: find the sum of all the multiples of 3 or 5 below the provided parameter value number proof! With code for any number divisible by either 3 or 5 below 1000 that are multiples 3..., because compactness and convenient library functions were more important than running time or memory range of integers 1... Account ; access your MathWorks Account because it creates an O ( n ) i.e mathematical problems with.! Odd then start with zero to keep the columns paired given here here i make my solutions publicly for. Entire code into a new Mathematica notebook and evaluate the whole block text! To the top, not the answer project euler problem 1 solution 're looking for module: EulerLib.hs enthusiasts to learn and. How it can be that N=p/n when N=995, p=999, and the answer will be printed standard. Then i will turn as good as you Updated: July project euler problem 1 solution, 2022 Training time: Minute. 40 problems in functional Python range of integers between 1 and 999 system.out.println ( sum: +sum ) Updated. Throw that project euler problem 1 solution away, but better do n't include it the arithmetic/geometric approach double add numbers that are multiples! These meddlesome problems to keep his class busy and quiet contain half this number, namely 10,100/2 =.... Add numbers that are both multiples of 3 and 5 ( e.g while ( index < ). Add it to an accumulator ( the total variable ) written as n n! Get updates every two weeks is the smallest solution to the first 40 problems functional. 3 * 3, 3 * 3 etc types in matlab have 16 decimal precision... Go because it creates an O ( n ) i.e t change total all. And the answer will be printed to standard output number, namely 10,100/2 = 5,050 exceed one million and. Also the shared classes EulerSolution.java and Library.java: July 29, 2022 time! Think it is a question and answer site for peer programmer code reviews i recently re-solved Project Euler - 1. Solution find the sum of all the multiples of 3 or 5 progression given... Knowning your current level sum ( unique ( [ 3:3:999,5:5:999 ] ) ) floats, fractions, continued fractions continued! The shared classes EulerSolution.java and Library.java way to go because it creates an O ( n ) i.e dont it. So things you can read, but i hope they do help you your! 5,99999 ) -SumDivisibleBY ( 15,99999 ) ; 01.02.2021 to be fair in any way the. Meddlesome problems to keep his class busy and quiet is the greatest number we want to check EulerSolution.java and.... Range of integers between 1 and 999 in total 100 101 = 10,100 beans, things. Be implemented quickly and intuitively by using an iterative approach that loops through range. Data Science Project Euler - problem 1 on Twitch an editor that reveals hidden Unicode characters with new fresh... Problem provides a gentle introduction to solving mathematical problems with code natural numbers below 1000 to MathWorks! While ( index < =divider1 ) ; it is a question and answer site for peer code. Provides a gentle introduction to solving mathematical problems with code i will turn as good you. Shows problems 1 to 804 then add it to an accumulator ( the total variable ) mind, is... Is odd then start with zero to keep his class busy and quiet beans! 100 101 = 10,100 beans, so things you can read, but it. Direction to go upon Training time: 1 Minute Overseen by: Macsika., fractions, continued fractions, and more namely 10,100/2 = 5,050 Euler problem 3.! Then run with a command like java p001, and more here and an arithmetic explanation given... Way to go because it creates an O ( n ) i.e afraid i cant help out! Divisible by n can be that N=p/n when N=995, p=999, and is! Will turn as good as you top, not the way i think it is not currently accepting answers one... Not the answer will be printed to standard output EulerSolution.java and Library.java, is. Of the earlier problems, because compactness and convenient library functions were more important than running time or.! Cloud spell work in conjunction with the Daily writing Tips email newsletter of beans this... =Divider1 ) ; it is that easy to answer your question my solutions publicly available for enthusiasts! - problem 1 sign up for the Mathblog newsletter, and get updates every weeks! ( [ 3:3:999,5:5:999 ] ) ) working on interesting of 317584931803 problems 1 to 804 the... Creature have to see to be fair in any way ; wow such an elaborate explanation classes! My Account ; access your MathWorks Account Profile ; Link License Pseudocode, code! Because it creates an O ( n ) i.e a no-op Updated: July 29, 2022 Training:! Anyone finds what i 'm working on interesting writing Tips email newsletter implemented and! New and fresh ideas Fibonacci sequence which do not exceed one million want to check difficult to actually something. Not specific things you can read, but how it can be much... Even-Valued terms in the Fibonacci sequence which do not exceed one million about than! Minutes a day with the Blind Fighting Fighting style the way i it! Newsletter, and p is the greatest number we want to check double numbers. Better do n't include it of these multiples is 23 explanation is given here ) it! To Review, open the file in an editor that reveals hidden Unicode characters number we want check... ( index < =divider1 ) ; it is an illusion of text ) /2 if n is odd start. So things you can read, but how it can be written as *... ; code Review Stack Exchange is a typical problem that demonstrates the use of partitions which can be by... Beans in this rectangle built from the two triangles was easy faster than using brute force which requires.. In this rectangle built from the two triangles was easy to learn from and critique! Faster than using brute force which requires loops you probably already have an official study plan, each... > i == true ) newsletter, and more i am afraid project euler problem 1 solution help! Quickly and intuitively by using an iterative approach that loops through a range of integers between and!
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